# A Derivation Ekman transport

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1. Feb 9, 2017

### ATY

Hey guys,
We tried to derive the ekman transport in a lecture. The assumptions we made are
1. constant density
2. stationarity
4. no vertical velocity.
So this is what the professor showed us:

But is this correct ? I thought that from stationarity we get $\frac{\partial}{\partial t}=0$ instead of $\frac{d}{dt} = 0$.
I would still get to the correct result using
$\frac{\partial u}{\partial x}=\frac{\partial v}{\partial x}=\frac{\partial v}{\partial y}=\frac{\partial v}{\partial x}=0$ and $w=0$ in order to eliminate all terms on the left side of the equation.
Can somebody help me ?

2. Feb 16, 2017