- #1

Can anyone please tell me how the formula for centripetal acceleration (a=v2/r) is derived?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter Lindsey
- Start date

- #1

Can anyone please tell me how the formula for centripetal acceleration (a=v2/r) is derived?

- #2

Doc Al

Mentor

- 45,433

- 1,886

You should be able to find this in any number of physics books. In any case, the basic idea is this:

An object in circular motion has at any point a tangential speed V= (omega)r. To find the acceleration, take two points separated by d(theta). Draw the vectors representing these two velocities. The difference between them (which points towards the center) is dV = Vd(theta). The acceleration a = dV/dt = Vd(theta)/dt = V(omega)= V(V/r) = V^{2}/r.

Hope this helps a little.

Just to be clear: omega is the angular speed, V is linear speed.

An object in circular motion has at any point a tangential speed V= (omega)r. To find the acceleration, take two points separated by d(theta). Draw the vectors representing these two velocities. The difference between them (which points towards the center) is dV = Vd(theta). The acceleration a = dV/dt = Vd(theta)/dt = V(omega)= V(V/r) = V

Hope this helps a little.

Just to be clear: omega is the angular speed, V is linear speed.

Last edited:

Share:

- Replies
- 15

- Views
- 316

- Last Post

- Replies
- 12

- Views
- 1K

- Last Post

- Replies
- 3

- Views
- 166

- Replies
- 4

- Views
- 300

- Replies
- 9

- Views
- 635

- Replies
- 9

- Views
- 332

- Replies
- 6

- Views
- 325

- Replies
- 3

- Views
- 718

- Last Post

- Replies
- 5

- Views
- 2K

- Replies
- 17

- Views
- 372