Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Derivation of E=mC2

  1. May 17, 2005 #1
    ¿How did Einstein derived that E=mC2?. ¿ Can I find an english translation of his original paper?.
     
  2. jcsd
  3. May 17, 2005 #2
    See
    http://www.fourmilab.ch/etexts/einstein/E_mc2/e_mc2.pdf
    (there is translated in english the second article Einstein published in Annalen der physik about special relativity -thanks dex, i missed last- in german)
     
    Last edited: May 17, 2005
  4. May 17, 2005 #3

    dextercioby

    User Avatar
    Science Advisor
    Homework Helper
    Insights Author

  5. May 18, 2005 #4
    thanks Rebel and dextercioby for the required information
     
  6. May 19, 2005 #5
    You can simply take this integral and you'll get [tex] E = mc^2 [/tex]

    [tex] \int^c_0{P dv} ; [/tex]

    where [tex] P = mv\gamma [/tex]

    and [tex] \gamma = \frac{1}{\sqrt{1 - (\frac{v}{c})^2}} [/tex]

    [tex] \int^c_0 {\frac{mv}{\sqrt{1 - (\frac{v}{c})^2}} dv = mc^2 [/tex]
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Similar Discussions: Derivation of E=mC2
  1. On E=mc2 (Replies: 1)

  2. Derivation of E=mc2 (Replies: 6)

Loading...