Derivation of normal and tangential forces of a rotor electric motor drives

[trinupab]

Hi all,

I'm currently undergoing a masters of science course in Mechatronics Engineering. One of my core modules is Electrical Components. I'm stuck in understanding one of the key parts in this module. I've been asked to derive the Tangential and Normal forces of the rotor shown below.
I've been going through the notes and all i know is Force = I*L*Bsin(teta). Aside from that i find no connection in u0 (miu not)

I would highly appreciate any feedback in this matter. I'm still new to this forum so i apologize for any mistakes caused.

Jay

 

[Valkarie]

.The tangential and normal forces can be calculated using the formula F = I*L*Bsin(theta) where I is the current, L is the length of the rotor, B is the magnetic field strength, and theta is the angle between the force vector and the magnetic field vector. The tangential force is the component of the force that is parallel to the rotor, and the normal force is the component of the force perpendicular to the rotor. To calculate the tangential force, use the equation Ft = I*L*Bsin(theta0) where theta0 is the angle between the force vector and the perpendicular to the rotor. To calculate the normal force, use the equation Fn = I*L*Bcos(theta0).