I was bored, so I decided to derive the special relativity formulae.(adsbygoogle = window.adsbygoogle || []).push({});

I drew the following diagram of a light clock:

In order to find t, I did sinθ=d/ct

Which gives tsinθ=d/c

Which gives t=d/csinθ

If v = 0, vt = 0, and θ = 90

sin90 = 1

t = d/csinθ = d/c

We call this t_{0}

If v is greater than 0, vt is greater than zero, and θ is less than 90

sin90 is less than1

t = d/csinθ is greater than d/c

We use Pythagoras to get t_{0}=t(1- (v^{2}/c^{2}))^{-1/2}

What are the steps involved in getting to this answer?

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# B Derivation of special relativity formulae

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