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Derivation of THp

  1. Jan 21, 2014 #1
    hi everyone can anyone please give me a clue of how to derive this equation

    Hp= Q(gpm)* Δp(psi)/1714

    Q is volumetric flow rate
    Δp is pressure
     
  2. jcsd
  3. Jan 21, 2014 #2

    SteamKing

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    1 HP = 33000 ft-lb/min.

    1 gal. water = 8.33 lbs

    for water, Δp = H * 144 in[itex]^{2}[/itex]/ft[itex]^{2}[/itex] / 62.4 lbs / ft,
    where H is the pump head in feet of water

    So

    HP = Q*H / 33000 = [Q gal/min * 8.33 lbs / gal * H feet of water * Δp * (144/62.4 lbs / ft[itex]^{2}[/itex])] / 33000

    HP = [Q * Δp * 8.33 * (62.4/144)] / 33000 = Q * Δp / 1714
     
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