Derivation of THp

  1. Jan 21, 2014 #1
    hi everyone can anyone please give me a clue of how to derive this equation

    Hp= Q(gpm)* Δp(psi)/1714

    Q is volumetric flow rate
    Δp is pressure
     
  2. jcsd
  3. Jan 21, 2014 #2

    SteamKing

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    2015 Award

    1 HP = 33000 ft-lb/min.

    1 gal. water = 8.33 lbs

    for water, Δp = H * 144 in[itex]^{2}[/itex]/ft[itex]^{2}[/itex] / 62.4 lbs / ft,
    where H is the pump head in feet of water

    So

    HP = Q*H / 33000 = [Q gal/min * 8.33 lbs / gal * H feet of water * Δp * (144/62.4 lbs / ft[itex]^{2}[/itex])] / 33000

    HP = [Q * Δp * 8.33 * (62.4/144)] / 33000 = Q * Δp / 1714
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted
Similar Discussions: Derivation of THp
  1. How was F=qvB derived? (Replies: 1)

Loading...