- #1

- 15

- 0

I think I need the formula: f(x) = 1/x^n than f'(x) = -n/x^n+1 but I'm not sure and don't know how to use it.

I know the answer is: -0.5 * x^-2 but have no idea why.

could someone explain this to me please?

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- Thread starter discy
- Start date

- #1

- 15

- 0

I think I need the formula: f(x) = 1/x^n than f'(x) = -n/x^n+1 but I'm not sure and don't know how to use it.

I know the answer is: -0.5 * x^-2 but have no idea why.

could someone explain this to me please?

- #2

- 9,559

- 770

[tex]\int x^n\, dx = \frac{x^{n+1}}{n+1}+C[/tex]

also works for negative exponents. Write your fraction as a negative exponent.

- #3

- 15

- 0

[tex]\int x^n\, dx = \frac{x^{n+1}}{n+1}+C[/tex]

also works for negative exponents. Write your fraction as a negative exponent.

thanks for your answer.

now how would I put 1/x³ into that formula to get -0.5 * x^-2 ?

- #4

- 9,559

- 770

thanks for your answer.

now how would I put 1/x³ into that formula to get -0.5 * x^-2 ?

Write 1/x³ as x

- #5

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- 0

I guess I should learn this formula, not only because it's a "familiar" one for you guys. But also because for some reason it's not on my formula sheet.

:) tnx for your help.

- #6

SteamKing

Staff Emeritus

Science Advisor

Homework Helper

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Link: http://en.wikipedia.org/wiki/Lists_of_integrals

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