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Derivative a from v (lorentz transform)

  1. Sep 23, 2005 #1
    :confused: derivating a from v (lorentz transform)


    v'=(v-u)/(1-vu/c^2), then dv'=? is it (dv-u)/(1-udv/c^2)?
  2. jcsd
  3. Sep 24, 2005 #2


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    What exactly are u, v, v'. Not values- what do they mean?
  4. Sep 25, 2005 #3
    I am not sure if the original function makes sense since dv/du=-fu/fv which is the drivative rule for implicit functions but this equation it doesn't work
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