Derivative a from v (lorentz transform)

[mntb]

Main Question or Discussion Point

derivating a from v (lorentz transform)

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v'=(v-u)/(1-vu/c^2), then dv'=? is it (dv-u)/(1-udv/c^2)?

 

[HallsofIvy]

What exactly are u, v, v'. Not values- what do they mean?

 

[jaap de vries]

I am not sure if the original function makes sense since dv/du=-fu/fv which is the drivative rule for implicit functions but this equation it doesn't work