Derivative a from v (lorentz transform)

  • Thread starter mntb
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  • #1
mntb
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:confused: derivating a from v (lorentz transform)

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v'=(v-u)/(1-vu/c^2), then dv'=? is it (dv-u)/(1-udv/c^2)?
 

Answers and Replies

  • #2
HallsofIvy
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What exactly are u, v, v'. Not values- what do they mean?
 
  • #3
jaap de vries
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I am not sure if the original function makes sense since dv/du=-fu/fv which is the drivative rule for implicit functions but this equation it doesn't work
 

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