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Derivative at a Point

  1. Feb 25, 2007 #1
    1. The problem statement, all variables and given/known data
    a)Find the equation of the tangent line to f(x) = (x - 6)^8 at the point where x = 7.

    b)The demand curve for a product is given by
    q = f(p) = 5,000e-0.30p,
    where q is the quantity sold and p is the price of the product, in dollars. Find f(6) and f'(6).

    2. Relevant equations
    a)sustitute x for 8

    b) to find F(6) i sutitute p for 6
    to find F'(6) i sustitute p for 6????

    3. The attempt at a solution

    a)the solution is 1 and this is incorrect

    b)in F(6)=826 this is correct
    in F'(6)=247.94 this is incorrect
  2. jcsd
  3. Feb 25, 2007 #2


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    Substitute x for 8??? What does that mean?

    Show us more of your work for finding the derivatives of these functions. Maybe we can point out what you're doing wrong.
  4. Feb 25, 2007 #3
    Keep in mind that you're finding an equation for part (a), and not a number.

    As hage567 said showing some work would be beneficial to all.
  5. Feb 26, 2007 #4


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    What is the derivative of (x- 6)8?
  6. Feb 26, 2007 #5
    Part A: If x=7 is the point of tangency, the slope of the tangent line to the function is the derivative of that function evaluated at the point x. So first find the derivative of your function, then evaluate it at the point of tangency. Given the slope, you can find the equation of the line given a set of points on that line.
  7. Feb 27, 2007 #6


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    It's clear that, after having posted this same problem repeatedly and being told, repeatedly, that he must show some effort himself, lolo105 is still expecting someone to do the problem for him!
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