If f(x)=x^3-x-6 and g is the inverse function of f.
what is f'(g(0))g'(0)?
the answer is 1...but im not sure how to get that.
The Attempt at a Solution
i wasnt quite sure, but i assumed g(x)=1/(x^3-x-6)
^is this assumption right?
i also set f(x)=0 to find x=2.
but for g(0) i get -1/6
so for f'(g(0))g'(0)= i get -1(-1/6)*(-1) = -1/6
but this is incorrect.