[tex]\frac{d}{dx} Xe^{lnX^2} = e^{lnX^2}+Xe^{lnX^2} \frac{1}{X^2} 2x[/tex](adsbygoogle = window.adsbygoogle || []).push({});

[tex]=\frac{X^2 e^{lnX^2}+Xe^{lnX^2}2X}{X^2} [/tex]

is that correct?

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# Homework Help: Derivative check

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