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Homework Help: Derivative check

  1. Mar 18, 2005 #1
    [tex]\frac{d}{dx} Xe^{lnX^2} = e^{lnX^2}+Xe^{lnX^2} \frac{1}{X^2} 2x[/tex]
    [tex]=\frac{X^2 e^{lnX^2}+Xe^{lnX^2}2X}{X^2} [/tex]

    is that correct?
     
    Last edited: Mar 18, 2005
  2. jcsd
  3. Mar 18, 2005 #2

    arildno

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    True enough, but since [tex]e^{ln(x^{2})}=x^{2}[/tex] there is an easier way to solve this..
     
  4. Mar 18, 2005 #3
    oh wow...

    [tex]3x^2[/tex]

    is that it?
     
  5. Mar 18, 2005 #4

    arildno

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    Right..:wink:
     
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