How do I take the derivative of f(x)=ln[x/(x-1)]? Thanks!
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Mar 31, 2008 #2 tiny-tim Science Advisor Homework Helper 25,789 249 Welcome to PF! Hi lreichardt! Welcome to PF! Just use the chain rule: derivative of ln, times the derivative of x/(x-1).
Welcome to PF! Hi lreichardt! Welcome to PF! Just use the chain rule: derivative of ln, times the derivative of x/(x-1).
Mar 31, 2008 #4 tiny-tim Science Advisor Homework Helper 25,789 249 ooh dear … better go the easy way … simplify it first … ln(x/(x-1)) = ln(x) - ln(x-1) … now differentiate!
ooh dear … better go the easy way … simplify it first … ln(x/(x-1)) = ln(x) - ln(x-1) … now differentiate!
Apr 6, 2008 #5 kelten 1 0 Chain rule = The difference of the derivative of the "Outer" and derivative of the "Inner", put simply.
Chain rule = The difference of the derivative of the "Outer" and derivative of the "Inner", put simply.