I am new to this forum, i don't know if it's here i should post this simple question.(adsbygoogle = window.adsbygoogle || []).push({});

I have to find the peak of the function:

##\frac{x}{\sqrt{x^2+R^2}(x^2+R^2)}=\frac{x}{(x^2+R^2)^{3/2}}##

I differentiate:

##\left( \frac{x}{(x^2+R^2)^{3/2}} \right)'=\frac{(x^2+R^2)^{3/2}+x\left( \frac{3}{2}(x^2+R^2)^{3\2}\cdot 2x \right)}{(x^2+R^2)^3}##

Only the numerator:

##(x^2+R^2)^{1/2}\left[ (x^2+R^2)^3+3x^2 \right]##

When i equal it to 0 i get, as one possibility:

##(x^2+R^2)^3=-3x^2##

And it's not good, since x has a value.

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# Derivative of a fraction

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