Derivative of a matrix

  • #1
93
0
Hello :smile:

I scratch my head on trying to express [tex]\partial_{x}[\det(\textbf{1}-\textbf{M})][/tex] , where [tex]\textbf{M}[/tex] is a square matrix whose elements depend on x, as an expression involving [tex]\textbf{M}[/tex] and/or [tex]\partial_{x}\textbf{M}[/tex].
For instance, I have painfully noticed that it is not equal to [tex]\det(\textbf{1}-\partial_{x}\textbf{M})[/tex] :biggrin:

Any help would be much apprciated :smile: TIA
 
Physics news on Phys.org
  • #2
Nevermind…
This is the theorem I'm looking for exactly :)
 

Suggested for: Derivative of a matrix

Replies
3
Views
577
Replies
2
Views
1K
Replies
3
Views
676
Replies
5
Views
785
Replies
8
Views
219
Replies
3
Views
1K
Replies
5
Views
693
Back
Top