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Derivative of a trig function

  1. Sep 28, 2007 #1
    real quick review needed, I'm working through the quotient rule on a problem and need the first derivative of:

    (1+tanx)

    is it simply equal to:

    (0 + sec^2x * 1)
    (sec^2 x)

    ??
     
  2. jcsd
  3. Sep 28, 2007 #2
    yes that's correct

    1 = 0, [tex]\tan{x}=\sec^2{x}[/tex]
     
  4. Sep 28, 2007 #3

    CompuChip

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    Geez, that's a nice identity.
    I wish I could use that on my exam, it would make life a lot easier :biggrin:
     
  5. Sep 28, 2007 #4
    lol, you know what i meant ;)
     
  6. Sep 28, 2007 #5

    CompuChip

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    Yeah, I know you meant

    1' = 0, [tex]\tan(x)' = \sec^2(x)[/tex]
    where [tex]' = \frac{\rm d}{{\rm d}x}[/tex].
     
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