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Derivative of Angular Momentum

  1. May 31, 2012 #1
    Why is it that partial derivative of Lx wrt x is zero?
    where: Lx (Angular momentum along x)

    Yes and for further info. they wrote beside this that dLx/dx =d(yPz - zPy)/dx = 0

    I guess it resulted from some determinant but I just could not figure it out.

    (This was a snatch of a problem in Poisson's Bracket)
  2. jcsd
  3. May 31, 2012 #2
    Do you know multivariable calculus? y and z are constants when differentiated with respect to x. Hence, the result.
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