Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Advanced Physics Homework Help
Derivative of basis vectors
Reply to thread
Message
[QUOTE="Orodruin, post: 6039655, member: 510075"] Based on some of his other threads, he is not using normalised basis vectors but ##\vec e_i = \partial_i \vec x## (which I usually would denote ##\vec E_i## or similar to underline that they are not necessarily unit vectors - however, there are some places in the literature where ##\vec e_i## is used and instead ##\hat i## or similar is used for normalised basis vectors). With my preferred notation, where ##\vec e_i## are normalised and ##\vec E_i = \partial_i \vec x##, you would have ##\vec E_r = \vec e_r## but ##\vec E_\theta = r \vec e_\theta## so indeed you would have ##\partial_\theta \vec E_r = \vec E_\theta/r##. [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Advanced Physics Homework Help
Derivative of basis vectors
Back
Top