Help! I haven't the slightest clue on how to do this... thanks in advance!
Mar 3, 2010 #1 MrGoodyear812 12 0 Help! I haven't the slightest clue on how to do this... thanks in advance!
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Mar 3, 2010 #2 Sweet_GirL 24 0 MrGoodyear812 said: Help! I haven't the slightest clue on how to do this... thanks in advance! [tex]y=cos^{x+7}(x)[/tex] Start by taking the natural logarithmic of both sides.
MrGoodyear812 said: Help! I haven't the slightest clue on how to do this... thanks in advance! [tex]y=cos^{x+7}(x)[/tex] Start by taking the natural logarithmic of both sides.
Mar 3, 2010 #3 MrGoodyear812 12 0 even the y? so i'd have: ln(y) = (x+7)ln(cos(x)) how do i get rid of the ln on the y? cause i knew it was a ln problem, just i dont know how to get rid of the ln on the y
even the y? so i'd have: ln(y) = (x+7)ln(cos(x)) how do i get rid of the ln on the y? cause i knew it was a ln problem, just i dont know how to get rid of the ln on the y
Mar 3, 2010 #4 homology 306 1 Don't worry about 'getting rid of the ln' yet. The problem is about taking derivatives, so take one and see what happens.
Don't worry about 'getting rid of the ln' yet. The problem is about taking derivatives, so take one and see what happens.
Mar 4, 2010 #5 Mark44 Mentor Insights Author 33,505 5,191 If you take the derivative of the left side, you should get (1/y)(dy/dx). On the right side, you should have the derivative of ((x + 7)ln(cos x)). Solve the resulting equation for dy/dx.
If you take the derivative of the left side, you should get (1/y)(dy/dx). On the right side, you should have the derivative of ((x + 7)ln(cos x)). Solve the resulting equation for dy/dx.