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Derivative of e^2

  • Thread starter Ryuk1990
  • Start date
  • #1
158
0

Homework Statement



Derivative of f(x) = x3 + e2


Homework Equations



Dex = ex

D constant = 0

The Attempt at a Solution



f'(x) = 3x2 + 0?

Is e2 treated as a constant?
 

Answers and Replies

  • #2
1,930
229

Homework Statement



Derivative of f(x) = x3 + e2


Homework Equations



Dex = ex

D constant = 0

The Attempt at a Solution



f'(x) = 3x2 + 0?

Is e2 treated as a constant?
Yes. Or you can use the chain rule. if u = f(x) = 2 and y = g(u) = [itex] e^u [/itex] then

[tex] \frac {dy} {dx} = \frac {dy} {du} \frac {du} {dx} [/tex]

since [tex] \frac {du} {dx} = 0 [/tex] [tex] \frac {dy} {dx} = 0 [/tex].
 
  • #3
33,173
4,858

Homework Statement



Derivative of f(x) = x3 + e2


Homework Equations



Dex = ex

D constant = 0

The Attempt at a Solution



f'(x) = 3x2 + 0?

Is e2 treated as a constant?
Not only is it treated as a constant, it is a constant. The derivative of any constant is zero. Period.

Using the chain rule certainly works, but it's definitely overkill, so not recommended.
 

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