# Derivative of e^2

## Homework Statement

Derivative of f(x) = x3 + e2

Dex = ex

D constant = 0

## The Attempt at a Solution

f'(x) = 3x2 + 0?

Is e2 treated as a constant?

## Homework Statement

Derivative of f(x) = x3 + e2

Dex = ex

D constant = 0

## The Attempt at a Solution

f'(x) = 3x2 + 0?

Is e2 treated as a constant?

Yes. Or you can use the chain rule. if u = f(x) = 2 and y = g(u) = $e^u$ then

$$\frac {dy} {dx} = \frac {dy} {du} \frac {du} {dx}$$

since $$\frac {du} {dx} = 0$$ $$\frac {dy} {dx} = 0$$.

Mark44
Mentor

## Homework Statement

Derivative of f(x) = x3 + e2

Dex = ex

D constant = 0

## The Attempt at a Solution

f'(x) = 3x2 + 0?

Is e2 treated as a constant?
Not only is it treated as a constant, it is a constant. The derivative of any constant is zero. Period.

Using the chain rule certainly works, but it's definitely overkill, so not recommended.