- #1

- 158

- 0

## Homework Statement

Derivative of f(x) = x

^{3}+ e

^{2}

## Homework Equations

De

^{x}= e

^{x}

D constant = 0

## The Attempt at a Solution

f'(x) = 3x

^{2}+ 0?

Is e

^{2}treated as a constant?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter Ryuk1990
- Start date

- #1

- 158

- 0

Derivative of f(x) = x

De

D constant = 0

f'(x) = 3x

Is e

- #2

- 2,005

- 288

## Homework Statement

Derivative of f(x) = x^{3}+ e^{2}

## Homework Equations

De^{x}= e^{x}

D constant = 0

## The Attempt at a Solution

f'(x) = 3x^{2}+ 0?

Is e^{2}treated as a constant?

Yes. Or you can use the chain rule. if u = f(x) = 2 and y = g(u) = [itex] e^u [/itex] then

[tex] \frac {dy} {dx} = \frac {dy} {du} \frac {du} {dx} [/tex]

since [tex] \frac {du} {dx} = 0 [/tex] [tex] \frac {dy} {dx} = 0 [/tex].

- #3

Mark44

Mentor

- 34,825

- 6,568

Not only is it treated as a constant, it## Homework Statement

Derivative of f(x) = x^{3}+ e^{2}

## Homework Equations

De^{x}= e^{x}

D constant = 0

## The Attempt at a Solution

f'(x) = 3x^{2}+ 0?

Is e^{2}treated as a constant?

Using the chain rule certainly works, but it's definitely overkill, so not recommended.

Share: