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Derivative of e^x^x^2?

  1. Oct 25, 2007 #1
    derivative of e^x^x^2??

    can someone explain to me how this could be solved?

    so far i have:
    lnf(x)= x^2lne^x)

    (e and ln cancel?)

    f'(x)/f(x)= (x^2)x
    f'(x)= f(x) x^3

    = (e^x^x^2)(x^3)??

    is that right? or do i need to use the power rule or something?
  2. jcsd
  3. Oct 25, 2007 #2


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    use the fact that if [tex]Y=u^v[/tex]
    then [tex]\frac{1}{Y}\frac{dY}{dx}=\frac{v}{u}\frac{du}{dx}+\frac{dv}{dx}lnu[/tex]
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