Derivative of e^x^x^2?

  • Thread starter erjkism
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  • #1
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derivative of e^x^x^2??

can someone explain to me how this could be solved?

so far i have:
f(x)=e^x^x^2
lnf(x)= x^2lne^x)

(e and ln cancel?)

f'(x)/f(x)= (x^2)x
f'(x)= f(x) x^3

= (e^x^x^2)(x^3)??


is that right? or do i need to use the power rule or something?
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
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31
[tex]y=e^{x^{x^2}}[/tex]
[tex]lny=x^{x^2}[/tex]
use the fact that if [tex]Y=u^v[/tex]
then [tex]\frac{1}{Y}\frac{dY}{dx}=\frac{v}{u}\frac{du}{dx}+\frac{dv}{dx}lnu[/tex]
 

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