- #1

- 7

- 0

## Homework Statement

find the derivative of: 4e^t((e^2t)-(e^t))

## Homework Equations

d/dx[b^x] = lnb(b^x)d/dx(x)

## The Attempt at a Solution

I tried subtracting the two exponents in the brackets as well as multiplying it out. both wrong. Help?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter Quarkn
- Start date

- #1

- 7

- 0

find the derivative of: 4e^t((e^2t)-(e^t))

d/dx[b^x] = lnb(b^x)d/dx(x)

I tried subtracting the two exponents in the brackets as well as multiplying it out. both wrong. Help?

- #2

- 1,045

- 2

[tex]4e^{t}(e^{2t}-e^{t})[/tex] ?

You should make it easier on yourself and distribute that [itex]4e^{t}[/itex] through the parenthesis and then take the derivative. Remember to use the chainrule, for example, recall that:

[tex]\frac{d}{dx}e^{f(x)}=e^{f(x)}\frac{df(x)}{dx}[/tex]

- #3

Mentallic

Homework Helper

- 3,798

- 94

## Homework Statement

find the derivative of: 4e^t((e^2t)-(e^t))

## Homework Equations

d/dx[b^x] = lnb(b^x)d/dx(x)

## The Attempt at a Solution

I tried subtracting the two exponents in the brackets as well as multiplying it out. both wrong. Help?

So just to be clear, you are trying to find

[tex]\frac{d}{dt}\left(4e^t\left(e^{2t}-e^t\right)\right)[/tex]

Correct?

I tried subtracting the two exponents in the brackets

[tex]e^{2t}-e^t\neq e^t[/tex]

if that's what you were implying. Remember the rules for subtracting indices are

[tex]\frac{a^b}{a^c}=a^{b-c}[/tex]

When you multiplied the factor out (expanded) what did you get?

Share: