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How do I find the derivative of f(x)=(square root x^2-2x)^3-9(square rootx^2-2x)
[tex]f(x) = (\sqrt{x^2 - 2x})^3 - 9\sqrt{x^2 - 2x}[/tex]candynrg said:How do I find the derivative of f(x)=(square root x^2-2x)^3-9(square rootx^2-2x)
That's the product rule. Power rule:PhysicsinCalifornia said:For the power rule, for
[tex]f(x)g(x) [/tex], the derivative is [tex]f'(x)g(x) + g'(x)f(x)[/tex]