- #1

- 27

- 0

Find the derivative of the function: [tex]\frac{x^3-3x^2+4}{x^2}[/tex]

I brought the denominator to the top and multiplied it out to get [tex]{x-3+4x^-2}[/ltex]. I then took the derivative of that to get [tex]{1-0-8x^-3}[/tex], which can be simplified to [tex]\frac{-7}{x^3}[/tex].

However, in the back of my book, the answer is given as [tex]\frac{x^3-8}{x^3}[/tex].

Please enlighten me as to where i went wrong.