Derivative of ln(x): Proof and Explanation

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In summary, the derivative of ln(x) is 1/x because ln(x) is the inverse of the exponential function, e^x. This can be proven using the definition of a derivative and the derivative of ln(x) can be negative for values of x less than 1. The derivative of ln(x) represents the slope of the tangent line to the graph of ln(x) and they have a reciprocal relationship.
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omri3012
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Hallo,

Does anybody knows why does the derivative of ln(x) is
1/x , if anyone has a link for a formal proof it will be very
helpful.

Thanks,
Omri
 
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This area is for learning materials as the name says, not for questions.

I have answered this question in a private message.
 

What is the derivative of ln(x)?

The derivative of ln(x) is 1/x.

Why is the derivative of ln(x) equal to 1/x?

This is because ln(x) is the inverse of the exponential function, e^x. Therefore, the derivative of ln(x) is the inverse of the derivative of e^x, which is 1/x.

How do you prove the derivative of ln(x) using the definition of a derivative?

To prove the derivative of ln(x) using the definition of a derivative, we start by writing out the definition: f'(x) = lim(h→0) [(f(x+h) - f(x)) / h]. Then, we substitute ln(x) for f(x) and simplify the expression until it becomes 1/x.

Can the derivative of ln(x) be negative?

Yes, the derivative of ln(x) can be negative for values of x less than 1. This is because the natural logarithm function is only defined for positive values of x and its derivative is negative for values less than 1.

What is the relationship between the derivative of ln(x) and the graph of ln(x)?

The derivative of ln(x) represents the slope of the tangent line to the graph of ln(x) at any given point. Therefore, the graph of ln(x) and its derivative have a reciprocal relationship, where the derivative is the inverse of the slope of the graph of ln(x).

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