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I just have a quick question about the derivative of ln(x). If i was to calculate the derivative of ln(x +1) = 1/(x+1), would I technically have to restrict the domain of the solution to x>-1?

Otherwise when I take the antiderivative again, I will have Ln|x+1| (note the absolute value) and not the original function.

One other question that I sort of implied to be fact, if i take the integral of 1/x, where x>0, is the solution now Ln(x) rather than Ln|x|?

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# Derivative of Ln(x)

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