If we have a function of the form(adsbygoogle = window.adsbygoogle || []).push({});

Ln(ax)

Is it the case that the derivative is simply 1/x no matter what the initial value of 'a' might be? Or do we take into account 'a' in some way

The thing i need clarifying is this.... If we have Ln(3x), the derivative is 1/x, but the integral of 1/x is not Ln(3x). How can this be so?

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# Homework Help: Derivative of Natural Log

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