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Qube

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**Derivative of exponential function**

## Homework Statement

f(x) = 4^x + e^(2tanx)

find f'(0)

## Homework Equations

I used log differentiation.

y = 4^x + e^(2tanx)

lny = xln4 + 2tanx(lne) = xln4 + 2tanx

## The Attempt at a Solution

y'/y = ln4 + 2sec^2(x)

Solving for y I get y = 2.

Plugging in x = 0 I get:

y'/2 = ln4 +2sec^(0) = ln4 + 2(1)

y' = 2(ln4+2)

This however, isn't the answer.

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