Derivative of secant

  • Thread starter Karol
  • Start date
  • #1
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Homework Statement


Find dy/dx for ##~y=\sec^2(5x)##

Homework Equations


Secant and it's derivative:
$$\sec\,x=\frac{1}{\cos\,x}$$
$$\sec'\,x=\tan\,x\cdot\sec\,x$$


The Attempt at a Solution


$$y=\sec^2(5x)~\rightarrow~y'=2\cdot 5 \cdot \sec(5x)\tan(5x)\sec(5x)=10\tan(5x)\sec^2(5x)$$
The answer should be:
$$y'=-\frac{2x+1}{2}\frac{1}{\sqrt{(x^2+x-1)^3}}$$
 

Answers and Replies

  • #3
1,380
22
Thank you very much jambaugh
 

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