- #1
devilazy
- 15
- 0
1. As the title states, I need to fine d/dx(sinx+cosx)secx.
2. I am given pretty much most of the derivatives and trig functions.
3. Here's my attempt to solve the question:
y=(sinx+cos)secx
y'=(sinx+cosx)(secxtanx)+(secx)(cosx-sinx)
=sinxsecxtanx+cosxsecxtanx+cosxsecx-sinxsecx
=secx(sinxtanx+cosxtanx+cosx-sinx)
and that's where I've gotten up to.
So now I'm curious if my last step is the final answer, or can I simplify it more. I know some can be switched around but I'm not sure if that would help make the answer. Please advice and thanks for the help in advance!
2. I am given pretty much most of the derivatives and trig functions.
3. Here's my attempt to solve the question:
y=(sinx+cos)secx
y'=(sinx+cosx)(secxtanx)+(secx)(cosx-sinx)
=sinxsecxtanx+cosxsecxtanx+cosxsecx-sinxsecx
=secx(sinxtanx+cosxtanx+cosx-sinx)
and that's where I've gotten up to.
So now I'm curious if my last step is the final answer, or can I simplify it more. I know some can be switched around but I'm not sure if that would help make the answer. Please advice and thanks for the help in advance!