1. As the title states, I need to fine d/dx(sinx+cosx)secx. 2. I am given pretty much most of the derivatives and trig functions. 3. Here's my attempt to solve the question: y=(sinx+cos)secx y'=(sinx+cosx)(secxtanx)+(secx)(cosx-sinx) =sinxsecxtanx+cosxsecxtanx+cosxsecx-sinxsecx =secx(sinxtanx+cosxtanx+cosx-sinx) and that's where I've gotten up to. So now I'm curious if my last step is the final answer, or can I simplify it more. I know some can be switched around but I'm not sure if that would help make the answer. Please advice and thanks for the help in advance!