Finding derivative of (sin(sqt3x+5))
None given. Chain Rule
The Attempt at a Solution
The answer is: (cos(sqrt3x+5)) * 1/2(sqrt3x+5) * 3
but I don't know how to get to the 3.
I turned sin into cos and multiplied by the inside derivative giving the first two parts of the answer. How do I get 3? - is that from the inside derivative of 3x+5? How do you know which is outside or inside of a derivative