Derivative particle problem

  • #1
I have this function (to calculate potential for classical over-barrier model if you're wondering) where qp and qt are both (different) particle charges:

V(a,R) = -(qp /R) - [qt / (R-a)]

What is dV/da?

The maximum of the function occurs when dV/da = 0, and I need to solve for a. So does solving for a yield R[1 + sqrt(qt/qp)]^-1?

Thanks
 
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Answers and Replies

  • #2
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the-rocketman said:
I have this function (to calculate potential for classical over-barrier model if you're wondering) where qp and qt are both (different) particle charges:

V(a,R) = -(qp /R) - [qt / (R-a)]

What is dV/da?
use the chain rule.
 
  • #3
Hm... but it has 2 variables. I havent had any multivariable calc.
 
  • #4
sic
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what?
try to sketch the function. obviously, the function doesn't have a maximum for any constant R.
what is the question from the beginning?
 
  • #5
R and a are not constants, they are the variables. the constants are the q values
 
  • #6
the-rocketman said:
The maximum of the function occurs when dV/da = 0...
That isn't necessarily true for multivariable functions. Instead, you need to see when the gradient vector [dV/da, dV/dR] = 0 and use the discriminant to tell what type of critical point it is.
 
  • #7
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the-rocketman said:
Hm... but it has 2 variables. I havent had any multivariable calc.
the process is the same. just imagine that R isn't a variable, so long as you want to find dV/da.

(the "d's" should be curly, like so: [tex]\partial[/tex])
 
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