I have to find the min and max of this function using derivatives:
(e^(-x)) - (e^(-2x))
The Attempt at a Solution
f'(x) = -e^(-x) + 2x(e^(-2x))
So now i set that to zero, and I get...
2x(e^(-2x)) = e^(-x)
And at this point I have no idea what to do. If you divide e^-x by e^-2x can u do something with the exponents?