1. The problem statement, all variables and given/known data Find the derivative of: cube root of (1/(2-3x)) 2. Relevant equations use chain rule (i think?):(f of g)'(x) = f'(g(x))*g'(x) 3. The attempt at a solution first, i changed the cube root to the exponent 1/3. second, i did the derivative and came up with 1/((1/(2-3*x))^(2/3)*(2-3*x)^2) now i think i need to cancel out the 1/(2-3*x))^(2/3), but i'm not sure how to go about it. ---i kinda cheated and went on maple to see if my answer was close, and it came up as 1/(9*x^2-12*x+4), and i knew i had to factor the last part of the denominator, but i don't understand how the first part of the denominator disappeared. thanks for all of your help!