(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the derivative of: cube root of (1/(2-3x))

2. Relevant equations

use chain rule (i think?):(f of g)'(x) = f'(g(x))*g'(x)

3. The attempt at a solution

first, i changed the cube root to the exponent 1/3.

second, i did the derivative and came up with 1/((1/(2-3*x))^(2/3)*(2-3*x)^2)

now i think i need to cancel out the 1/(2-3*x))^(2/3), but i'm not sure how to go about it.

---i kinda cheated and went on maple to see if my answer was close, and it came up as 1/(9*x^2-12*x+4), and i knew i had to factor the last part of the denominator, but i don't understand how the first part of the denominator disappeared.

thanks for all of your help!

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# Homework Help: Derivative question?

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