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Derivative using chain rule

  1. Apr 8, 2008 #1
    I am trying to find the first and second derivative using the chain rule of the following:

    u sin(x^2)

    This is what I have but I don't think it is correct. Can someone pls let me know?

    first derivative: u * 2x cos(x^2) + sin(x^2) u'

    second derivative:
    u * 2( x * -2sin(x^2) + cos(x^2)) + 2xcos(x^2)* u' + sin(x^2)*u" + u'* 2xcos(x^2)

    Any help thanks
  2. jcsd
  3. Apr 8, 2008 #2
    If u is a function of x and you are differentiating with respect to x, then it looks correct to me.
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