- #1

i can solve x^x but adding this new x just confuses me any help will do, X^x^x

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- Thread starter silence
- Start date

- #1

i can solve x^x but adding this new x just confuses me any help will do, X^x^x

- #2

Lonewolf

- 337

- 1

Do you mean (x^x)^x or x^(x^x)? I'm assuming the former.

- #3

sorry i meant x^(x^x)

- #4

Lonewolf

- 337

- 1

- #5

- #6

djuiceholder

- 8

- 0

ok ok

Last edited:

- #7

arildno

Science Advisor

Homework Helper

Gold Member

Dearly Missed

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but can you do (x^x)^x ??

it seems impossible

1. It is not at all imposible; note that this equals: [tex](x^{x})^{x}=x^{x^{2}}[/tex]

Rewriting this as:

[tex]x^{x^{2}}=e^{x^{2}\ln(x)}[/tex]

We may readily differentate this by means of the chain rule, yielding the derivative:

[tex]x^{x^{2}}(2x\ln(x)+x)[/tex]

2. Please do not re-open nearly 6-year old threads.

- #8

djuiceholder

- 8

- 0

ok ok

Last edited:

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