# Derivative x^x^x

#### silence

i can solve x^x but adding this new x just confuses me any help will do, X^x^x

#### Lonewolf

Do you mean (x^x)^x or x^(x^x)? I'm assuming the former.

#### silence

sorry i meant x^(x^x)

#### Lonewolf

Glad you picked that one. Get something like ln(y) = xxln(x) and use the product rule. Don't forget you already know d(xx)/dx

#### silence

wow i never noticed that i was doing it a long way which would have come out wrong anyways. thanks for the help

ok ok

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#### arildno

Homework Helper
Gold Member
Dearly Missed
but can you do (x^x)^x ??
it seems impossible
1. It is not at all imposible; note that this equals: $$(x^{x})^{x}=x^{x^{2}}$$
Rewriting this as:
$$x^{x^{2}}=e^{x^{2}\ln(x)}$$
We may readily differentate this by means of the chain rule, yielding the derivative:
$$x^{x^{2}}(2x\ln(x)+x)$$

ok ok

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