VietDao29 said:The tangent line equation to the graph of f(x) at the point (x0, f(x0)), is:
y - f(x0) = f'(x0) (x - x0)
Now that you have f'(x), what you have to do is to find f'(x0).
In (1), if x0 = -1, then what's f(x0)? What's f'(x0)?
Can you go from here? :)
No, if f'(x) = -6x + 4, then you can find f'(-1) by simply replacing every x in f'(x) by -1, like this:Hollysmoke said:Would f'(xo) be the derivative? or -6x+4, so I would substitute
[-6(1)+4]-[6x+4] / x - 1 ?
What do you mean by this????Hollysmoke said:Also, any help for the 2nd one?