# Homework Help: Derivatives, chain rule

1. Nov 9, 2013

### physics604

1. Find the derivative of y=e$\sqrt{x}$

2. Relevant equations

Chain rule

3. The attempt at a solution

y=eu

$\frac{dy}{du}$
= ueu-1

u=$\sqrt{x}$

$\frac{du}{dx}$= $\frac{1}{2}$x-1/2

$\frac{dy}{dx}$= $\sqrt{x}$e$\sqrt{x}$-1 × $\frac{1}{2}$x-1/2

= $\sqrt{x}$ $\frac{e^\sqrt{x}}{e}$ × $\frac{1}{2\sqrt{x}}$

= $\frac{e^\sqrt{x}}{2e}$

The answer to this question is $\frac{e^\sqrt{x}}{2\sqrt{x}}$. What did I do wrong?

Any help is much appreciated.

Last edited: Nov 9, 2013
2. Nov 9, 2013

### physics604

Nevermind, I got it.

The derivative of e^x is still e^x.