I suggest going back and reading the problem again! You were asked to find y'(1). How about setting x= 1?Dough said:i am not sure what else y have to do to get the answer, i wrote that out as well as
-1 = x^2 + 3x -5
solved and got x = 1 or -3...
but what else?
dy/dx = f'(x^2 + 3x - 5)(2x + 3)