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Derivatrive of f question

  1. Sep 20, 2004 #1
    Find the derivative of f when :

    [tex]\sqrt{x}(2x-7)[/tex]

    When put into product rule form (following (f '*g) + (f*g') )

    [tex](\frac{1}{2}x^\frac{-1}{2})\ast(2x+7) + \sqrt{x}(2)[/tex]

    Just started today making sure I am on the right track.
     
    Last edited: Sep 20, 2004
  2. jcsd
  3. Sep 20, 2004 #2
    i am pretty sure this is actually the answer when in product rule

    [tex](\frac{1}{2}x^\frac{-1}{2})\ast(2x+7) + \sqrt{x}(2)[/tex]
     
  4. Sep 20, 2004 #3
    Ahh yes...My fault doubled it twice.. thanks.
     
  5. Sep 20, 2004 #4
    hmm my fundamentals are screwed up, I forgot what happens here for the most part. with the fraction exponents and the radicals.

    Factor the [tex](\frac{1}{2}x^\frac{-1}{2})[/tex] in to the [tex](2x+7)[/tex] ?
     
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