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Derive equation for RLC circuit

  1. Nov 24, 2011 #1
    how to get this equation:
    Vout/Vin = [RL]/[-[ω][/2]+jω(R/L)+1/(LC)]
     
  2. jcsd
  3. Nov 24, 2011 #2
    - Show us the picture of the RLC Circuit your using.
    - Tell us how Vout is defined.
    - Tell us what [omega][/2] stands for (use the boards LaTeX syntax).
     
  4. Nov 24, 2011 #3
    http://upload.wikimedia.org/wikipedia/en/1/14/RLC_series_band-pass.svg
     
  5. Nov 24, 2011 #4
    Hi Ai En,

    as a solution you could use the voltage divider formula to get a first equation:
    [tex]\frac{V_{out}}{V_{in}} = \frac{R_L}{R_L + j \omega L + \frac{1}{j \omega C}}[/tex]

    afterwards if you think thats useful you can try to manipulate this formula until you get the one given to you. Since i can not interpret your given equation (as i said use the LaTeX encoding to be more clear about your formula) i can only guess and did for example multiply the whole formula with [itex]\frac{j \omega L}{j \omega L}[/itex] and the denominator again with [itex]\frac{L}{L}[/itex] that results in:
    [tex]\frac{V_{out}}{V_{in}} = \frac{j \omega R_L}{L \cdot \left( - \omega^2 + j \omega \frac{R_L}{L} + \frac{1}{C L}\right)}[/tex]
     
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