Deriving atwood's gravity formual

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  • #1
foo_fighter@hotmail.
I have always been curios to how Atwood derived his formula a=g(m2+m1)/(m2-m1) to get gravity. Does anyone know how he did it? I have read that he used Netwons f=ma but I personally could not find a way to do this using newtons f=ma.

Thanks.
 

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  • #2
jcsd
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The formula is:

g = a(M1 + M2)/(M1- M2)

using F = ma and F = mg

Gravity is acting on both the weights therefore:

F1 = M1g

F2 = M2g

The total force acting down is given by:

F = F1 - F2

which is:

F = g(M1 - M2)

As the force is pulling both weights we can view the two weights as one single weight being acted on with a mass of M1 + M2, so using F = ma

F = a(M1 + M2)

We,ve now got two terms for the same force so we can subsitue in for F:

a(M1 + M2) = g(M1 - M2)


changing this around:

g = a(M1 + M2)/(M1- M2)

Q.E.D.
 
Last edited:

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