Deriving electric field strength in terms of retarded potentials

1. Dec 3, 2011

sk2nightfire

since, B=curl(A), curl(E)= -$\partial$B/$\partial$t
1)curl(E)=- $\partial$/$\partial$t(curl(A))
2)curl( E+$\partial$A/$\partial$t)=0
3)then since curl($\nabla$V)=0,

E +$\partial$A/$\partial$t =- $\nabla$V
E= -$\nabla$V -$\partial$A/$\partial$t

I'm confused about how to go from step 1 to step 2. The first thing I did was add the right side to the left to get: curl(E)+$\partial$/$\partial$t(curl(A))=0

I know there's a property that says
a X (b+c) = a X b + a X c

But what about the -$\partial$/$\partial$t ? How would I deal with that?

Thank you.

edit: perhaps this should be in the calculus section?

Last edited: Dec 3, 2011
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