Deriving Feynman rules out of a generating functional

• JD_PM
In summary, the conversation discusses the process of solving a problem involving computing partial derivatives and using Feynman rules and diagrams. The steps involved include studying relevant sections, computing the derivatives, and interpreting the results in terms of vertices and propagators. The next step is to use this information to draw Feynman diagrams for the problem. Guidance is requested for proceeding with this step.
JD_PM
Homework Statement
Given the generating functional (repeated indices in the same term are assumed to be summed over)

Z[w] := \frac{1}{(2 \pi)^{n/2}} \int d^n x \prod_{i=1}^n d \bar{\theta}_i d \theta_i \exp \left( -\bar{\theta}_i \partial_j w_i (x) \theta_j - \frac 1 2 w_i (x) w_i (x) \right) \tag{1}

We define

\begin{equation*}
w_i(x) := x_i + \frac 1 2 g_{ijk} x_j x_k, \quad \text{where} \quad g_{ijk} = g_{ikj} = g_{kij}
\end{equation*}

Where ##g_{ijk}## is assumed to be small.

a) Find the Feynman rules.

b) Find the one- and two-loop contributions to ##Z[g]##
Relevant Equations
N/A
To approach the problem I first studied section 1.3 and, more importantly, 1.4 of Osborn's notes.

We first need to compute ##\partial_j \omega_i (x)## and ##\omega_i (x)\omega_i (x)##

\begin{equation*}
\partial_j \omega_i (x) = \delta_{ij} + \underbrace{\partial_j (g_{ilm})}_{=0}x_l x_m + g_{ijk}x_k
\end{equation*}

\begin{align*}
\omega_i \omega_i &= \left( x_i + \frac 1 2 g_{ijk} x_j x_k\right) \left(x_i + \frac 1 2 g_{ilm} x_l x_m \right) \\
&= x_i x_i + \frac 1 4 g_{ijk} g_{ilm} x_j x_k x_l x_m + g_{ijk}x_i x_j x_k
\end{align*}

Plugging the given definition of ##\omega_i (x)## into ##(1)## yields

\begin{align*}
Z[w] &= \frac{1}{(2 \pi)^{n/2}} \int d^n x \prod_{i=1}^n d \bar{\theta}_i d \theta_i \exp \left( -\bar{\theta}_i \partial_j w_i (x) \theta_j - \frac 1 2 w_i (x) w_i (x) \right) \\
&= \frac{1}{(2 \pi)^{n/2}} \int d^n x \prod_{i=1}^n d \bar{\theta}_i d \theta_i \exp \Big( -\bar{\theta}_i \delta_{ij} \theta_j - g_{ijk} \bar{\theta}_i \theta_j x_k \\
&- \frac 1 2 x_i x_i -\frac 1 2 g_{ijk} x_j x_k - \frac 1 8 g_{ijk} g_{ilm} x_j x_k x_l x_m \Big) \\
&= \int \prod_{i=1}^n d \bar{\theta}_i d \theta_i \exp(-\bar{\theta}_i \delta_{ij} \theta_j ) \frac{1}{(2 \pi)^{n/2}} \int d^n x \exp\Big( -\frac 1 2 \vec x \cdot \vec x \\
&+ \vec b \cdot \vec x - V(x) \Big)
\end{align*}

Where

\begin{equation*}
b_k := g_{ijk} \theta_i \bar{\theta}_j, \quad \text{noticing} \quad \{ \theta, \bar{\theta}\} = 0
\end{equation*}

\begin{equation*}
V(x) = + \frac 1 2 g_{ijk} x_j x_k + \frac 1 8 g_{ijk} g_{ilm} x_j x_k x_l x_m
\end{equation*}

Next we work out the potential. Based on Osborn's (1.132)

I get

\begin{equation*}
V_i(x) = \frac 3 2 g_{ijk} x_j x_k + \frac 1 2 g_{ijk} g_{jlm} x_k x_l x_m
\end{equation*}

\begin{equation*}
V_{ij}(x) = 3 g_{ijk} x_k + \frac 1 2 \left( g_{ijk} g_{klm} x_l x_m + 2g_{ikl} g_{jkm} x_l x_m \right)
\end{equation*}

\begin{equation*}
V_{ijk}(x) = 3 g_{ijk} + g_{ijk} g_{klm} x_m + 2g_{ikl} g_{jkm} x_m
\end{equation*}

\begin{equation*}
V_{ijkl}(x) = g_{ijm}g_{klm} + 2g_{ikm} g_{jlm} x_m = 3g_{ijm}g_{klm}
\end{equation*}

At this point I should have all necessary tools to write down the Feynman rules and proceed with the diagrammatic interpretation. However I am struggling to see how I can proceed, in an analogous way Osborn did in section 1.4

Any guidance is much appreciated.

Thank you

Hello there,

Thank you for sharing your approach and progress so far. It seems like you have a good understanding of the mathematical calculations involved in solving this problem. However, as you mentioned, the next step would be to interpret these results in terms of Feynman rules and diagrams.

To do this, you can start by identifying the vertices in the potential function and assigning them appropriate factors. For example, the term ##g_{ijk}## can be interpreted as a vertex with three external legs corresponding to the fields ##\theta_i, \bar{\theta}_j## and ##x_k##. Similarly, the term ##g_{ijk}g_{jlm}## can be interpreted as a vertex with four external legs corresponding to the fields ##\theta_i, \bar{\theta}_j, x_k## and ##x_l##. You can continue this process for all terms in the potential, assigning the appropriate factors to each vertex.

Once you have identified the vertices, you can then draw the corresponding Feynman diagrams by connecting the external legs with propagators, which in this case would be the fields ##x_i##. The factors assigned to each vertex will determine the strength of the interaction in the diagram.

I hope this helps guide you in the right direction. If you have any further questions, please don't hesitate to ask. Good luck!

1. What is a generating functional?

A generating functional is a mathematical tool used in quantum field theory to calculate the probabilities of various particle interactions. It is a functional that takes in a set of parameters and outputs a probability amplitude for a specific interaction process.

2. How are Feynman rules derived from a generating functional?

Feynman rules are derived from a generating functional by using functional derivatives. These derivatives are taken with respect to the fields in the functional, and then the resulting expression is simplified using the equations of motion for the fields.

3. Why are Feynman rules important in quantum field theory?

Feynman rules are important because they provide a systematic way to calculate the probabilities of particle interactions in quantum field theory. They also allow for the visualization of these interactions through Feynman diagrams, making complex calculations more manageable.

4. How do Feynman rules help in understanding particle interactions?

Feynman rules help in understanding particle interactions by breaking down the complex calculations into simpler steps. They also provide a visual representation of the interactions through Feynman diagrams, which can aid in understanding the underlying physics of the interaction process.

5. Are there any limitations to using Feynman rules?

While Feynman rules are a powerful tool in quantum field theory, they do have some limitations. They are only applicable to perturbative calculations, and they may not accurately describe interactions at high energies or in extreme conditions, such as strong gravitational fields.

Replies
2
Views
1K
• Quantum Interpretations and Foundations
Replies
1
Views
495
Replies
4
Views
1K
Replies
1
Views
913
Replies
1
Views
2K
Replies
3
Views
1K
Replies
15
Views
1K
Replies
9
Views
2K