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Deriving 'G' from E=mc^2 and Gravitons

  1. Nov 12, 2003 #1
    What does the unit and magnitude of constant 'G' mean, and what is its relation with graviton? ANY OPINION?


    Here is how i see it:

    E=mc^2
    c^2=E/m where E=W=Fr (r stands for radius or distance or ‘s’)
    therefore c^2= Fr/m
    therefore c^2= c^2----when forces interact the forces hold true the constant c^2 in order to remain stable

    therefore Fr/m= Fr/m

    Fr/m=mar/m ----where F=ma
    Fr/mm=ar/m ----where a=F/m

    therefore Fr/mm=Fr/mm

    Fr/mm=Fvt/mm ----v=r/t where r=vt
    Fr/mm=Frt/tmm ----where v=r/t

    therefore Frt/mm=Frt/mm

    Frt/mm=Frr/vmm ----where t=r/v
    Frtv/mm=Frr/mm ----where v=r/t

    therefore Frr/mm=Frr/mm

    where F=(Frr/mm)mm/r^2 ----(Frr/mm) is proportionality for example: F=Kq1q2/r^2-electromagnetic force

    The "G" (=Frr/mm) is a way of expressing how the constant c is kept true mathematically when forces interact just the way c^2 is a mathematical expression expressing that c should always remain true in order for the matter to remain stable
     
    Last edited: Nov 12, 2003
  2. jcsd
  3. Nov 17, 2003 #2
    That don't make any difference.
     
  4. Nov 20, 2003 #3
    QuantumNet
    what doesen't make any difference?
    thanks
     
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