Deriving 'G' from E=mc^2 and Gravitons

  • Thread starter xeno
  • Start date
5
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What does the unit and magnitude of constant 'G' mean, and what is its relation with graviton? ANY OPINION?


Here is how i see it:

E=mc^2
c^2=E/m where E=W=Fr (r stands for radius or distance or ‘s’)
therefore c^2= Fr/m
therefore c^2= c^2----when forces interact the forces hold true the constant c^2 in order to remain stable

therefore Fr/m= Fr/m

Fr/m=mar/m ----where F=ma
Fr/mm=ar/m ----where a=F/m

therefore Fr/mm=Fr/mm

Fr/mm=Fvt/mm ----v=r/t where r=vt
Fr/mm=Frt/tmm ----where v=r/t

therefore Frt/mm=Frt/mm

Frt/mm=Frr/vmm ----where t=r/v
Frtv/mm=Frr/mm ----where v=r/t

therefore Frr/mm=Frr/mm

where F=(Frr/mm)mm/r^2 ----(Frr/mm) is proportionality for example: F=Kq1q2/r^2-electromagnetic force

The "G" (=Frr/mm) is a way of expressing how the constant c is kept true mathematically when forces interact just the way c^2 is a mathematical expression expressing that c should always remain true in order for the matter to remain stable
 
Last edited:

QuantumNet

That don't make any difference.
 
5
0
QuantumNet
what doesen't make any difference?
thanks
 

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