- #1

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**Assume: Hydrostatic Situation, ideal gas**

Use empirical formula T = T

Use empirical formula T = T

_{0}- BzI have rechecked my work several times and can't seem to find a mistake. The answer is supposed to be:

p

_{2}= p

_{1}((T

_{0}- Bz)/T

_{0})

^{(g/Bz)}

dp/dz = -ρg Now substitute ideal gas equation for ρ

dp = -(p/RT)g dz

∫(1/p) dp = (-g/R) ∫(1/(T

_{0}-Bz) dz After substituting

**T = T**Integrate

_{0}- Bz ...let u = T

_{0}- Bz

du = -B dz

ln(p

_{2}/p

_{1}) = (g/BR) ∫(1/u) du

ln(p

_{2}/p

_{1}) = (g/BR)(ln(u))

ln(p

_{2}/p

_{1}) = (g/BR)(ln(T

_{0}-Bz))

p

_{2}= p

_{1}(T

_{0}- Bz)

^{(g/BR)}

Where are they getting that T

_{0}on the bottom??