1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Deriving Laplace Transforms

  1. Jan 12, 2008 #1
    1. The problem statement, all variables and given/known data

    Derive the Laplace transform of the following functions, using first principles

    3d) [tex]u(t - T) \} = 0, \ t<T \ (= 1, t>T) [/tex]

    3e) [tex]f(t) = e^{-a(t-T)}u(t-T)[/tex]

    2. Relevant equations

    see above
    3. The attempt at a solution

    I know I need to derive the transform using by integration using this:

    L(f) = [tex]\int^\infty_{0} \mbox{f(t) e^{-st}} \ dt[/tex]

    but I don't understand the notation, is T the laplace transform of t ? Is u the unit step function? so u(s) = 1/s ?
    If someone could explain this to me please?
    Last edited: Jan 12, 2008
  2. jcsd
  3. Jan 12, 2008 #2


    User Avatar
    Science Advisor
    Homework Helper

    u is a function and T is a value for t, t is the variable.
  4. Jan 13, 2008 #3


    User Avatar
    Science Advisor
    Homework Helper

    Yes u is the stepfunction. You must use two useful identities in laplace transform theory.
  5. Jan 13, 2008 #4


    User Avatar
    Homework Helper

    u is *defined* in the problem. yes, it is a step function, but the step does not occur at zero. tell us: where does the step occur?
    no. u depends on T as a parameter, so too will the transform depend on T as a parameter. if T happened to be zero then you *would* be correct, but T is not (necessarily) zero.
    your teacher or professor or whoever obviously wants you to evaluate the integral that defines the transform. The first one should be very easy if you know how to integrate an exponential function by itself. I.e., do you know the value of this integral
    \int_a^b e^x

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Deriving Laplace Transforms