1. The problem statement, all variables and given/known data A projectile is fired with initial speed Vo at an angle Θ above the horizontal over flat ground. a. show that the distance d that the projectile goes and height h reached by the projectile are given by: d = (Vo^2 sin2Θ)/g h = (Vo^2 sin^2Θ)/2g 2. Relevant equations X = VT Vx = V(cosΘ) Vy = V(sinΘ) T = d / Vo(sinΘ) 3. The attempt at a solution d = (Vo^2 sin2Θ)/g Vt = (Vo^2 sin2Θ)/g (Vocos(Θ))(d / Vosin(Θ)) = (Vo^2 sin2Θ)/g dcot(Θ) = (Vo^2 sin(2Θ)/g dcot(Θ) = (Vo^2 * 2sin(Θ)cos(Θ))/g Then this is where I get lost. If I do divide cotangent of theta then would distance be proved. I haven't started on height yet.