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## Homework Statement

A projectile is fired with initial speed Vo at an angle Θ above the horizontal over flat ground.

a. show that the distance d that the projectile goes and height h reached by the projectile are given by:

d = (Vo^2 sin2Θ)/g

h = (Vo^2 sin^2Θ)/2g

## Homework Equations

X = VT

Vx = V(cosΘ)

Vy = V(sinΘ)

T = d / Vo(sinΘ)

## The Attempt at a Solution

d = (Vo^2 sin2Θ)/g

Vt = (Vo^2 sin2Θ)/g

(Vocos(Θ))(d / Vosin(Θ)) = (Vo^2 sin2Θ)/g

dcot(Θ) = (Vo^2 sin(2Θ)/g

dcot(Θ) = (Vo^2 * 2sin(Θ)cos(Θ))/g

Then this is where I get lost.

If I do divide cotangent of theta then would distance be proved.

I haven't started on height yet.