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Deside g`(π/3)

  1. Mar 22, 2014 #1
    1. The problem statement, all variables and given/known data

    Deside g`(π/3) when g(u)= (e^cosu-1/2)-6sin2u

    2. Relevant equations
    g`(π/3) when g(u)= (e^cosu-1/2)-6sin2u

    3. The attempended solutions
    ended upp with g`(u) = -12cosu-(e^cosu) sinu

    g´(π/3)= -12cos(π/3)-(e^cos(π/3)) sin(π/3)
    = -7.43 that dosen´t seem right..
     
  2. jcsd
  3. Mar 22, 2014 #2

    SammyS

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    You will need to use enough parentheses to remove ambiguity regarding your function.

    Is the 1/2 an exponent?

    Is that sin(2u) or is it sin2(u) ?

    etc.
    ...

    .
     
  4. Mar 22, 2014 #3
    Oki
    g(u)=ecos(u)-1/2-6sin(2u)

    g´(π/3)= -12cos(π/3)-ecos(π/3)sin(π/3)
    = -7.43 that dosen´t seem right..
     
  5. Mar 22, 2014 #4

    SammyS

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    It's not right.
     
  6. Mar 22, 2014 #5
    So i figure, where did i mess up , all is it all wrong ??
     
  7. Mar 22, 2014 #6
    You made errors when using the chain rule (twice). I would go back and review that and revisit this problem after.
     
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