# Homework Help: Deside g(π/3)

1. Mar 22, 2014

### SwedishFred

1. The problem statement, all variables and given/known data

Deside g(π/3) when g(u)= (e^cosu-1/2)-6sin2u

2. Relevant equations
g(π/3) when g(u)= (e^cosu-1/2)-6sin2u

3. The attempended solutions
ended upp with g(u) = -12cosu-(e^cosu) sinu

g´(π/3)= -12cos(π/3)-(e^cos(π/3)) sin(π/3)
= -7.43 that dosen´t seem right..

2. Mar 22, 2014

### SammyS

Staff Emeritus
You will need to use enough parentheses to remove ambiguity regarding your function.

Is the 1/2 an exponent?

Is that sin(2u) or is it sin2(u) ?

etc.
...

.

3. Mar 22, 2014

### SwedishFred

Oki
g(u)=ecos(u)-1/2-6sin(2u)

g´(π/3)= -12cos(π/3)-ecos(π/3)sin(π/3)
= -7.43 that dosen´t seem right..

4. Mar 22, 2014

### SammyS

Staff Emeritus
It's not right.

5. Mar 22, 2014

### SwedishFred

So i figure, where did i mess up , all is it all wrong ??

6. Mar 22, 2014

### scurty

You made errors when using the chain rule (twice). I would go back and review that and revisit this problem after.