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Engineering and Comp Sci Homework Help
Design of 4 stroke IC engine from few parameters (bmep, B.P, piston speed)
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[QUOTE="jack action, post: 4392499, member: 240508"] No, it is just to «convert» it to proper units. To convert your «wrong» answer (B[SUB]wrong[/SUB]) to the «right» answer (B[SUB]right[/SUB]), starting from your final answer, going backward: [LIST=1] [*]Your bore B of 364 mm must be converted to your assumed 3,64 dm ( = B[SUB]wrong[/SUB]/100 dm) [*]Then, it has to be squared to go back into the B² X n equation. So it becomes (B[SUB]wrong[/SUB]/100)² [*]This is where you've introduced incorrectly a 1000 multiplier that you have to remove. So it becomes (B[SUB]wrong[/SUB]/100)²/1000. At this point your displacement will be in the correct unit of m³. [*]Now to find again your bore dimension, you will need to go from B² to B, so it becomes sqrt((B[SUB]wrong[/SUB]/100)²/1000) or B[SUB]wrong[/SUB]/100/sqrt(1000). [*]Finally, you multiply it by 1000 to convert your m into mm. So you get B[SUB]wrong[/SUB]*1000/100/sqrt(1000). [/LIST] Hence B[SUB]right[/SUB] = B[SUB]wrong[/SUB]*1000/100/sqrt(1000) Or B[SUB]right[/SUB] = B[SUB]wrong[/SUB]* 0.31623 Improper unit conversion can make weird and unexpected results. [/QUOTE]
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Design of 4 stroke IC engine from few parameters (bmep, B.P, piston speed)
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