Basically our task is to design a inclined manometer. with these parameters : the maximum pressure: 7875pa minimum pressure: -3200. what im struggling on is calculating the angle that the manometer should be inclined at. Another parameter that is given is that the angle must be between 0-45 degrees to the horizontal. We are given also the sensitivity that it should be which is 1.77.(adsbygoogle = window.adsbygoogle || []).push({});

the diameter of the vertical tube is 22mm which is constant. the inclined tube has 3 sperate tubes of a 8mm diameter each, therefore the diameter of the inclined tube can be altered.

i have these formulas:

change in pressure = specific gravity of liquid in manometer times L(the column length) times the sin of the angle.

So far i know from theory, if you apply a certain amount of pressure, the fluid would displace a certain amount. Now in the vertical tube, the displacement change in h and in the inclined tube, it would be change in l. The volume of the amount that has been displaced is constant.. So i have made an equation which states that:

change in h * cross-sectional area in the vertical tube of the displaced h= change in l*cross-sectional area in the inclined tube of the displaced l .

Any help would be much appreciated as im extremely extremely extremely extremely extremely stuck

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# Designing a manometer

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